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combine and simplify (1/3)(cube root of 81)
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\[\sqrt[3]{81}=\sqrt[3]{9\times9}=\sqrt[3]{3\times3\times3\times3}\]
So now we can pull a three out from under the radical since it is a cube root and we have at least 3 3s under the radical
\[\sqrt[3]{3\times3\times3\times3}=3\sqrt[3]{3}\]
Now we multiply this by 1/3\[1/3\times3\sqrt[3]{3}=\sqrt[3]{3}\]
Hope this helps :)
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