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expand (x-5y)^7 using pascal's triangle
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can anyone help me?
you have to use combinations 7C0 = 1 7C1 = 7 7C2 = 21 7C3 = 35 7C4 = 35 7C5 = 21 7C6 = 7 7C7 = 1 Now the rule looks like this (x-5y)^7 = (7C0)*x^(7-0)*(-5y)^0 + (7C1)*x(7-1)*(-5y)^1 +... see the pattern
not exactly
can someone help me work it out i dont understand at all
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