what are the x-intercepts and mininum point(s) for the equation x^2+8x+16

Question

anonymous · Answer

Do you know how to factor?

anonymous · Answer

kinda

anonymous · Answer

That is how you find the x-intercepts.

You are wanting factors of 16 that add to get 8
1 * 16  ?
2 * 8 ?
4 * 4?

which one?

anonymous · Answer

4 and 4????

anonymous · Answer

Good so it factors into  (x + 4)(x + 4)

anonymous · Answer

So you take each of those and solve for each of them = 0

x + 4 = 0       (since they are both the same you only do this once)
x = -4

so this graph only touches the x-axis at -4

anonymous · Answer

If your x^2 term is positive then the graph opens upward and you have a minimum

if your x^2 term is negative then the graph opens downward and you have a maximum

anonymous · Answer

Since the x^2 term is positive it opens upward... since it only crosses one time on the x-axis, it MUST be the minimum   (-4,0)