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Mathematics 21 Online
OpenStudy (cherrilyn):

With integration by parts, evaluate the integral of xsec^2xdx

OpenStudy (cherrilyn):

nvm!

OpenStudy (anonymous):

x sec^2x= x.Int( sec ^2x)- Int[ Int( sec ^2x). d/dx x]dx x.tanx-Int[ tanx.1 dx] xtanx- ln(cosx)

OpenStudy (anonymous):

lol

OpenStudy (cherrilyn):

thanks uzma I got the same answer as you!

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