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OpenStudy (anonymous):
e^(-x/2) * 2e^(-4x)
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OpenStudy (anonymous):
what is e^a*e^b?
OpenStudy (anonymous):
e^(a+b) maybe? but i wans't sure 2e^(-4) = 2*e^(-4) or not
OpenStudy (anonymous):
yes it is
OpenStudy (anonymous):
oh okay thank you!
OpenStudy (anonymous):
you are welcome.
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