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Mathematics 7 Online
OpenStudy (anonymous):

I have the problem down to e9-1/6 how do I come up with x=?

OpenStudy (nowhereman):

You should be more careful with your notation. What you mean according to the previous question is \[x = \frac{e^9 - 1}{6}\] And either you calculate an numeric approximation, or just leave it in this form.

OpenStudy (anonymous):

The diagonal of a square A is (x+y). The diagonal of a square B with twice the area of A is

OpenStudy (anonymous):

x = 1 ---(e^9 - 1) 6 in your calculator you find e^9 then subtract 1 and then divide by 6

OpenStudy (amistre64):

tag

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