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Mathematics 19 Online
OpenStudy (anonymous):

I have that the sum from n to infinity of n*(2/3)^(n-1) is 9. Why?

OpenStudy (anonymous):

a summation of the form n^n is hardly close to 9.

OpenStudy (anonymous):

oh, nevermind, (2/3)^n

OpenStudy (nikvist):

OpenStudy (anonymous):

Medal for nikvist :)

OpenStudy (anonymous):

Sorry for still not entirely getting it, but... Where does the (2/3) S come from in the second step? how does it go from 3 to 9 at the end? Thanks

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