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I have that the sum from n to infinity of n*(2/3)^(n-1) is 9. Why?
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a summation of the form n^n is hardly close to 9.
oh, nevermind, (2/3)^n
Medal for nikvist :)
Sorry for still not entirely getting it, but... Where does the (2/3) S come from in the second step? how does it go from 3 to 9 at the end? Thanks
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