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A cliff diver falls forward from a cliff 130 feet above the ground. His position function is given by s(t) -16t^2 +130, where t is measured in seconds and s is measured in feet. After how many seconds will he be traveling at -40 ft/s?
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Take the derivative of s(t) and set it equal to -40 ft/s then solve for time.
Thanks, I got 1.25 sec. How about how far he would have fallen by that time?
you substitute t=1.25 into your derivative
substitute it into v'(t)?
or s(t) since it said "how far?"
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How do I find the average velocity for [0, 2]?
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