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dy/dx=y+2, solve for the differential equation...
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log(y+2)=x + C
So I'm assuming that i just multiply dx to the other side and then subtract y
hm. ln and log are the same thing right?
no ln(x)=2.303 log(x)
:s how did you get an x out of the equation lol?
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what do u mean??
you have log(y+2)=x+C, where did the x come from?
ok i;ll explain u u have dy/dx=y+2 then separate them ,u'll get dy/y+2=dx then integrate both side u'll get log(y+2)=x+c
ahhhhhhhh!! thank you! :D thank you thank you :)
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