Question

Find the Vertex and all Intercepts of the parabola.

f(x)=2x^2-4x

This is a practice one; however I am having trouble understanding how to get to the point where I need to sketch it on the graph and determine my values..

Answer 1

Do you know how to complete the square?

Answer 2

And are you in a calculus course?

Answer 3

Not really...I've been looking at this and i'm completely lost. Strange, but when i get to this type of problem, I go blank. Obviously I can graph it, but can't figure out how to solve it.

Answer 4

Well finding the intercepts is easy enough.
For the x-intercepts we will set y= 0
For the y-intercepts we will set x=0
For the vertex read this: http://www.purplemath.com/modules/sqrvertx.htm

Answer 5

y = x(2x - 4) set y = 0
which means either x = 0 or 2x-4=0 x=2,

Answer 6

Tell me if you need clarification on anything! =D

Answer 7

Ill look at that link to see if I can figure out the vertex
Thank you for your help