Determine the domain and range of y= $$\pm \sqrt{4-x^{2}}$$ and y= -(x/4-2x)
I know the domain are continuous everywhere, but I forgot how to determine the range.

Question

anonymous · Answer

Are you sure it is continuous everywhere? The square root sign and a denominator seems to be saying otherwise.

anonymous · Answer

It is continous everywhere EXCEPT at + or - 2

anonymous · Answer

yea, I made a mistake I was thinking of something else. Can youhelp me determine the range?

anonymous · Answer

The range would positive infinity to minus infinity

anonymous · Answer

You can cheat and punch in your calculator and you will see that you have horizontal asymptotes.

anonymous · Answer

I'm sorry vertical.