Question

Can someone show me how to work this out?
32x^3-28x^2-87x-27 divide by 8x+3

Answer 1

Are you studying long division?

Answer 2

Do you know synthetic division?

Answer 3

yes, long division, factoring polynomials

Answer 4

Just a minute

Answer 5

How many times does 8x go into 32x^3 or you can ask yourself what is
32x^3 divided by 8x?

Answer 6

would it be 4x^3, but how do if figure out the rest -28x^2-87x-27?

Answer 7

It would be 4x^2 because you already have 1 of the x's with the 8x

8x(4x^2) = 32x^3

This is a long process...

so... put 4x^2 above the 32x^3 and multiply 4x^2 (8x+3) and put that under the polynomial

Answer 8

4x^2
------------------------
8x + 3 | 32x^3 - 28x^2 - 87x - 27
32x^3 + 12x^2

Answer 9

Now draw a line under the bottom part, change the signs

32x^3 + 12x^2 becomes

-32x^3 - 12x^2 and then add.

you should end up with -40x^2

Answer 10

oh ok, it is easier to "see" this way..thank you

Answer 11

4x^2
------------------------
8x + 3 | 32x^3 - 28x^2 - 87x - 27
-32x^3 - 12x^2
--------------
-40x^2 = 87x

then you ask yourself 8x times what is -40x^2 and put that above the -28x^2 and repeat the process

Answer 12

India, have you figured out what to multiply 8x to get -40x^2? Don't give up.

Answer 13

Sorry that is a - 87 not an = 87x

Answer 14

That polynomial will factor to 3 binomials.

Answer 15

Earth to India, have you quit?

Answer 16

(4x-9)(x+1)(8x+3)

Answer 17

You need to practice the long division method.

Answer 18

Thank you, I understood blexting explained it. Thanks again

Answer 19

Oh O.K. I thought you might of got stuck on the 8x times ? =40x^2. Good to hear you crossed that hurdle. Good luck