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Determine whether the graphs of y=-2/3x and 3x-2y=6 are perpendicular lines
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perpendicular lines have opposite reciprocal slopes so both eqn need to be in slope-int form (y=mx+b) to determine slope (m-coefficient of x) in first equation m=-2/3
3x-2y=6 2y=3x-6 y=3/2 x - 3
m=-2/3 m=3/2 they are opposite reciprocals (flip numerator and denominator) so yes the lines are perpendicular
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