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im trying to solve question " (3x+4)/(7-x) x (5-2x)/(7-x) help with steps!? please.
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(3x+4)(5-2x)/(7-x)^2
THE ANSWER IS EASY the solution is following
\[(3x+4)\div(7-x) \times(5-2x)\div(7-x)\]
Now multiplying denominators of both the terms and also the numerators
we will get: (3x+4)times(5-2x)div(7-x)^2
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(15x - 6x^2 + 20 - 8x )/49 + x^2 - 14x
(7x - 6x^2 +20 ) / 49 +x^2 - 14x
SO HAVE U UNDERSTAND THE SOLUTION OR NOT MAR7407
IF YES THAN GIVE ME A MEDAL
thanks
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