Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
looks like someones trying to get there homework/test done ;)
OpenStudy (amistre64):
how you like the new openstudy sstar?
OpenStudy (amistre64):
multiply top and bottom by 2xy right?
x^2-y^2
---------
4x+4y
OpenStudy (anonymous):
\[\frac{\frac{x}{2y}- \frac{y}{2x}}{\frac{2}{y}+\frac{2}{x}} \]\[= \frac{x^2-y^2}{2yx}.\frac{xy}{2x+2y} = \frac{xy(x-y)(x+y)}{4yx(x+y)} = \frac{(x-y)}{4}\]
Correct me if I'm wrong ^_^
OpenStudy (anonymous):
I like it very much amistre ^_^, it's very nice!
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (amistre64):
divide by your favorite way of dividing...long hand prolly
x/4 -y/4
-----------------
4x +4y | x^2 -y^2
-x^2 -xy
-----------
-xy -y^2
xy + y^2
----------
0
x/4 - y/4 = (x-y)/4 yor right :)