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sqrt 6 (2sqrt 3 - 4 sqrt 2)
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\[\sqrt{6}(2\sqrt{3}-4\sqrt{2)} you need \to distribute the \sqrt{6}\]
\[2\sqrt{18}-4\sqrt{12}\]
take out 9 as a perfect square and 4 as a perfect square
\[2\sqrt{9*2} - 4\sqrt{4*3}\]
2*3\[2*3\sqrt{2} - 4*2\sqrt{3}\]
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\[6\sqrt{2}-8\sqrt{3}\]
do you understand that
yes thank you
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