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what are the solutions to 2y^2-16=8y
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not factorable?
i dont think so
it would not come out even and integer, but the solutions are 2(1-sqrt(3)), and 2(1+sqrt(3))
2y2-8y-16=0 y2-4y-8=0 y= 4+- sqrt(16+32) /2 y= 4+- 4 sqrt3 /2 y= 2+- 2 sqrt3
solve b using the quadradic equation
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Ya that's what I did
thank you!
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