Question

how do i find the solution set of x squared-4x-12=0

Answer 1

Use the quadratic equation.

Answer 2

which is?...

Answer 3

\[ax^2 + bx + c = 0 \implies x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}\]

Answer 4

If you haven't learned that yet, you can solve this by factoring also.

Answer 5

ok, can you help me with the factoring part please

Answer 6

Oh, is it (x-6)(x+2) then x-6=0 add 6 to both sides = x=6 then x+2=0 sub. 2 from both sides and get x=-2 so it 6 and -2?
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Answer 7

Yes. exactly!

Answer 8

thankyouu !!

Answer 9

Any time =)