Question

What is the area of the trapezoid given X=13 , y=9 and A = 55 degree?
A.)164.5cm^2
B.)210.3cm^3
C.)133.9cm^2
D.)267.8cm^2
*sn the picture is there when you click on the picture. Please help thanks

Answer 1

Height of the trapezoid can be found be taking the sin 55

Sin is opposite/hypothenuse Sin 55 = h/19
Sin 55 = h
7.37 = h

You also need to know the two bases.. The one base is x which is 13.
The other base is 13 + whatever 2 of those extra lengths are.
The extra lengths are the cos 55..
cos 55 = L/9
9 cos 55 = L
5.16 = L

So the other base is 5.16 + 13 + 5.16 = 23.32

The formula for area of a trapezoid is 1/2h(b1 + b2)

A = 1/2 * 7.37(13 + 23.32)
A = 133.9 cm^2

Answer 2

so its c