Question

Please help
Evaluate the polynomial function for the given values of the variable
P(s)=2sᶟ-9s-10 P(1/2) and P(0)

Answer 1

p(1/2)= 2 * (1/2)^3 - 9*(1/2) - 10

Answer 2

P(1/2) = P(s) with s = 1/2

Answer 3

P(1/2) = -57/4
P(0) = -10

Answer 4

so set s = 1/2 and 0 in your equation and evaluate it.

Answer 5

http://m.wolframalpha.com/input/?i=2x^3-9x-10%2C+x%3D1%2F2&x=0&y=0

Answer 6

thank you but i would like to work the problem myself step by step so i can do it on my own

Answer 7

Then just plug in the values 1/2 and 0 to the functions.

Answer 8

Ok.... do it by your self, and then check the answers using wolfram

Answer 9

i dont know how i havent done this kind of math in along time will u explain it step by step

Answer 10

So are you having problems multiplying, adding and subtracting with a fraction?

Answer 11

yes i am i hate fractions never been good at them

Answer 12

okay. lets take this one step at a time
P(s)=2sᶟ-9s-10
s = 1/2
P(1/2) = 2 * (1/2)^3 - 9(1/2) -10

Answer 13

(1/2)^3 = 1/2*1/2*1/2 = 1/8
2(1/2)^3 = 2*1/8 = 1/4
9(1/2) = 9/2
so,
P(1/2) = 1/4-9/2-10

Answer 14

9/2 is nothing but 18/4
and 10 is nothing but 40/4
so,
P(1/2) = 1/4 - 18/4 - 40/4 = (1-18-40)/4 = -57/4

Answer 15

2(1/2)^3=
how did u get 2*1/8

Answer 16

what \[(1/2)^3\]
its (1/2) *(1/2) *(1/2)= 1/8 but dont forget 2
2/8 = 1/4