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Conic sections: 4y^2+24y+16X+33=0. I'm studying on my own with library material. I need this written in standard form. I came up with: (y+3)^2=-4(x+1.5). The text has a different answer. I need to find Vertex, directrix, axis of symmetry, and focus. Because my answer is different from the text, these are off...
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Thank you. I see my error now! I'd added nine to both sides rather than 36 to the right when I completed the square!
4(y^2 + 6Y ) = -16x - 33 4(y^2 + 6Y + 9) = -16x - 33 + 36 4(y + 3)^2 = -16x + 3 (y+3)^2 = -4x + .75
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