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The perimeter of a triangle is 42 centimeters. The longest side is 2 centimeters less than the sum of the other two sides. Twice the shortest side is 4 centimeters less than the longest side. Find the lengths of each side of triangle please
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Let x denote the length of the longest side and y and z the length of the other 2 sides. Now y+z-2 = x so perimeter = x+y+z = 42 that is x+2+x=42 that is x = 20 and 2y = x-4 that is 2y = 16 that is y = 8 that is z = 14
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