Question

can someone please help me solve 15x^4-14x^2+3=0

Answer 1

15x4-9x2-5x2 +3=0
3x2(5x2-3)-(5x2-3)=0

Answer 2

(3x2-1)(5x2-3)=0

Answer 3

(3x^2-1)(5x^2-3)=0
+-Sqrt[3/5]
+-1/Sqrt[3]

Answer 4

u r cute

Answer 5

Thanks and how am i suppose to write that answer

Answer 6

\[x \in\left\{\pm \sqrt{3/5}; \pm1/\sqrt{3} \right\}\]

Answer 7

15x4-9x2-5x2 +3=0
3x2(5x2-3)-(5x2-3)=0
(3x2-1)(5x2-3)=0
3x2-1=0 , 5x2-3=0
x2=1/3, x2=3/4
x=+-1/sqrt3 , x=+- sqrt3 /2

Answer 8

where r u from?

Answer 9

sc

Answer 10

sc?

Answer 11

Scotland?

Answer 12

and u are from

Answer 13

south cakcalaki

Answer 14

australia

Answer 15

whoops :) Im from Czech republic :)

Answer 16

what grade r u in?

Answer 17

me or dollar?

Answer 18

both

Answer 19

I dont know your educational system. Im on hight school and im finishing it on 2012

Answer 20

ankur u mean -1 sq root 3, and -3/2

Answer 21

college

Answer 22

x=1/sqrt3, +-1/sqrt3 , x= sqrt3 /2, - sqrt3 /2

Answer 23

you have error there

Answer 24

it is sqrt(3/5) not (3/4)

Answer 25

serychj im confused on which answer to put

Answer 26

mine is correct :) his have error in one line before end:
5x2-3=0
x2=3/4 -> error x^2=3/5

Answer 27

sorry guys but all the answers were wrong after a couple of tries it generates the correct answer and it was -sq3/3,sq3/3,and -sq15/5,sq15/5 thanks anyway

Answer 28

check this: http://www.wolframalpha.com/input/?i=15x^4-14x^2%2B3%3D0
your wrong