Question

how would I factor 2b^4-32?

Answer 1

2(b4-16)
=2(b^4 - 2^4)
=2(b^2-2^2)(b^2+2^2)
=2(b- sqrt2)(b+ sqrt2)(b^2+2^2)

Answer 2

First factor out the 2:
\[2(b^4-16)\]
Then, note that it is in the form of \[a^2-b^2=(a-b)(a+b)\]
\[2(b^4-16)=2[ (b^2)^2-4^2 ]\]\[=2(b^2+4)(b^2-4)\]

Answer 3

thanks