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OpenStudy (anonymous):
Most racetracks consists 1st 2nd and 3rd place finishers in a perticular race in a proper order. if they are 10 entries in the race, how many tickets must be purchaced to grarentee a win?
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OpenStudy (dumbcow):
i think they want the number of different 1st,2nd,3rd arrangements possible among 10 entries use permutations 10P3 = 10!/(10-3)! = 10*9*8
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