Question

can someone help me find the solutions for this problem please?

Answer 1

\[(3x+8)^{2}-4(3x+8)-77=0\]

Answer 2

its a disguised quadratix; just substitute a = 3x+8

a^2 -4a -77 = 0

Answer 3

(a-11)(a+7)

Answer 4

a = 11 or a = -7

11 = 3x + 8 or -7 = 3x + 8

Answer 5

I actually got to the second step there. Just not sure where to go from there

Answer 6

11 - 8 = 3x
3 = 3x

x = 1

Answer 7

-7 -8 = 3x

-15 = 3x

x = -5

Answer 8

okk. yeah this was simpler than I thought. So the answer just comes to 11 and -7?

Answer 9

the answer for "a" is 11 and -7; but use that to figure out "x"

a = 3x +8 becomes

11 = 3x+8 and -7 = 3x+8.....solve for x

Answer 10

hmm okay. Just to make sure I understand what the next step looks like could you show me?

Answer 11

you mean more than the two times I jsut did :)

Answer 12

I think one of them is 1..

Answer 13

sorry. I'm a visual learner and I want to make sure i'm doing it right :)

Answer 14

we substituted a variable for (3x+8); right? I used a = 3x+8

we found that a = 11 and a = -7; so use that for solving for x.

11 = 3x+8
11-8 = 3x
3 = 3x

x = 1

Answer 15

a = -7

-7 = 3x+8
-7-8 = 3x
-15=3x

x = -5

Answer 16

okk that makes sense. I guess there were most steps than I thought. So now the answers are 1 and -5 I take it? Unless this problem never ends..

Answer 17

more*

Answer 18

:) x = 1 and x = -5 are the solutions to the problem :)

Answer 19

Thanks so much

Answer 20

youre welcome :)