11.) Refer to right triangle ACB. If m Ang A = 30° and BC = 5, what is the length of AC? Ang C=90
5 sqrt(2)
5
5 sqrt(3)
10

Question

11.) Refer to right triangle ACB. If m Ang A = 30° and BC = 5, what is the length of AC?  Ang C=90
  5 sqrt(2)  
  5  
  5 sqrt(3)  
  10

anonymous · Answer

Alright given the angles:
A=30
B=60 *(180-90-30)*
C=90
Given the sides:
a=5

Use the Law of Sines:
Lengh AC also known as b
b= 5/sin(30  (sin(60)
b= 8.66

anonymous · Answer

Sorry, but still don't understand. So, the lengh of AC =8.66. Should that # be rounded because that # is not in the answers?

anonymous · Answer

Let me double check something...Did the problem give you the degrees for Angle A and C?
If so then according to the Law of Sines length of AC would be 8.66 or something withing reasonable range...like 9.

anonymous · Answer

Angle A =30 and angle C= 90

anonymous · Answer

Yea answer is ~8.66