Question

Find the angle between the given vectors to the nearest tenth of a degree:
U=4i + 5j, V=7i - 4j

Answer 1

teh angle between vector is:

cos(t) = U*V/|U||V|

Answer 2

<4, 5>
<7,-4>
--------
28 -20 = 8; so the top is 8;

Answer 3

sqrt(16+25) * sqrt(49 + 16) is the bottom

Answer 4

8
----------; take the cos^-1 to get the angle
sqrt(41*65)

Answer 5

if its greater than the cos^1(7/sqrt(65)) you need to adjust for a different quadrant

Answer 6

Wow, I did this problem like twice and couldn't get it, I put the wrong number in for the second i.....lol Thanks a bunch!!!

Answer 7

It's 81.1 deg

Answer 8

angle = 81.08; but check the other one :)

Answer 9

that angle seems larger than ....your right, my senility kicked in for a moment lol

Answer 10

XD