Find the angle between the given vectors to the nearest tenth of a degree:
U=4i + 5j, V=7i - 4j

Question

amistre64 · Answer

teh angle between vector is:

cos(t) = U*V/|U||V|

amistre64 · Answer

<4, 5> <7,-4> -------- 28 -20 = 8; so the top is 8;

amistre64 · Answer

sqrt(16+25) * sqrt(49 + 16) is the bottom

amistre64 · Answer

8
----------; take the cos^-1 to get the angle
sqrt(41*65)

amistre64 · Answer

if its greater than the cos^1(7/sqrt(65)) you need to adjust for a different quadrant

anonymous · Answer

Wow, I did this problem like twice and couldn't get it, I put the wrong number in for the second i.....lol Thanks a bunch!!!

anonymous · Answer

It's 81.1 deg

amistre64 · Answer

angle = 81.08; but check the other one :)

amistre64 · Answer

that angle seems larger than ....your right, my senility kicked in for a moment lol

anonymous · Answer

XD