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OpenStudy (anonymous):
a^2+b^2=25,and a^3+b^3=91.find a and b
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OpenStudy (anonymous):
see ur solution is following
OpenStudy (anonymous):
do u know what is the formula of a^3 + b^3
OpenStudy (anonymous):
do u mean (a+b)(a+b)(a+b)=(a^2=2ab+b^2)(a+b)
OpenStudy (anonymous):
no
OpenStudy (anonymous):
then i am lost
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OpenStudy (anonymous):
THE VALUE OF a^3 + b^3 = (a+b)(a^2 - ab + b^2)
OpenStudy (anonymous):
a^2 + b^2 = 25
OpenStudy (anonymous):
(a+b)(25-ab)
OpenStudy (anonymous):
91 = (a+b)(25-ab)
OpenStudy (anonymous):
are u understanding
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OpenStudy (anonymous):
yap following
OpenStudy (anonymous):
u must know that 3^2 + 4^2
OpenStudy (anonymous):
= 25
OpenStudy (anonymous):
put the value of a and b respectively to 3 and 4 in the equation a^3 + b^3 = 91
OpenStudy (anonymous):
u will get 27 + 64
that is 91
so a = 3
and b=4
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OpenStudy (anonymous):
did u understand
OpenStudy (anonymous):
if yes than give me medal for this solution thanx
OpenStudy (anonymous):
yap.tq sir
OpenStudy (anonymous):
give me medal
OpenStudy (anonymous):
hey do u knw me if no than how u said me sir
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OpenStudy (anonymous):
i use to it by calling my teacher "sir".how to give you medal
OpenStudy (anonymous):
click on the icon GIVE MEDAL on the right side of the message i m giving u
and also need not say me sir i m in 8th grade and u???????????
OpenStudy (anonymous):
bye
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