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Evaluate the Indefinite Integral 2u(u^2+1)^2 du
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D(u^2 +1 ) = 2u
Try using substitution and let x = u^2 + 1
lol.......trig sub ;)
not so much trig sub but regular substitution
x = u^2 + 1 dx = 2u du \[\int\limits_{}^{}x^2dx = \frac{1}{3}x^3 = \frac{1}{3}(u^2 + 1)^3\]
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...trig sub!!... its all I can do ;)
amistre loves his trig subs
trig sub tis; trig sub that; but the trig sub tshirt and ride the rides.....trig sub!!!!
ROFLLL!!
chiaroscuro - was that your final answer? It's actually a multiple choice question and I can't seem to figure out if I got the right answer or if it's "none of the above"
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1/3 (u^2 + 1)^3
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