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OpenStudy (anonymous):
Evaluate the indefinite Integral: (2x / sqrt of 1-x^4) dx My answer: arcsin(x^4) + C
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OpenStudy (anonymous):
it's arcsin(x^2) + c
OpenStudy (anonymous):
\[2x \div \sqrt{1-xd^4}\]
OpenStudy (anonymous):
so fast! short cut method?
OpenStudy (anonymous):
lol it's the arcsin formula
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