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Mathematics 14 Online
OpenStudy (anonymous):

Evaluate the indefinite Integral: (2x / sqrt of 1-x^4) dx My answer: arcsin(x^4) + C

OpenStudy (anonymous):

it's arcsin(x^2) + c

OpenStudy (anonymous):

\[2x \div \sqrt{1-xd^4}\]

OpenStudy (anonymous):

so fast! short cut method?

OpenStudy (anonymous):

lol it's the arcsin formula

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