Question

f(x)=3x^2-2x-1 find equation of the line tangent parallel to line y=4x-8

Answer 1

is the question to find a line tangent to f(x) that is also parallel to the line y = 4x - 8?

Answer 2

if yeah
f'(x) = 6x - 2
4 = 4x - 2
x = 3/2
y = 3(3/2)^2 - 2(3/2) - 1
y = 27 / 4 - 4 = 11 / 4

y = mx + b
11/4 = 4(3/2) + b
b = 11/4 - 6
b = -13/4

y = 4x - 13/4