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OpenStudy (anonymous):
Factor and solve for x: 10ax^2 - 23ax - 5a ?
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OpenStudy (anonymous):
Uh. sorry, Not solve for x. Just factor >_<
OpenStudy (anonymous):
a ( 2x - 5 ) ( 5x + 1 ) You can verify by FOIL these
OpenStudy (anonymous):
Thank you so much!
OpenStudy (anonymous):
no problem, glad i could help
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