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if 7^(x-1)=6^x what is x?
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Gonna need a log or an ln to solve this one.
yeah, but how?
when i do x-1 log 7 = x log 6 and divide by log 7, the x just cancels out. and im supposed to solve for x..
Brush up a little operation of logs. Bring one one side then you have log a - lob b = log a/b
Don't lose your parens too.
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\[(x-1)log 7 = x log 6\] Distribute that log 7 to each term, bring all the terms with x to one side of the equation, etc. etc.
thansk! =D that makes sense!
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