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hey its a log and i can't explain it
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log x^(1/3) = [ log x ] ^ ( 1/2)
1/3 log x = ( log x ) ^1/2
square both sides
1/9 (log x )^2 = log x
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1/9 (log x)^2 - log x = 0
log x ( 1/9 log x - 1 ) = 0
so i factored there. log x = 0 or 1/9 log x - 1 = 0. so x = 1 or log x = 9, so x = 1 or x = 10^9, assuming log is base 10
thanks
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