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6x^4-17x^2+5=0
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write 17 as sum of 15 and 2
if u = x^2 then: 6x^4-17x^2+5 =0 | | | | 6u^2 -17u +5 =0
when you know the values for "u"; you can solve for "x"
x= sqrt(3)/3, sqrt(10)/2
+- cow....+- ;)
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mr.cow how would i write that
\[\pm \frac{\sqrt{3}}{3}, \pm \frac{\sqrt{10}}{2}\]
im suppose to solve the equation for x when i key that in its saying incorrect answer
did you split up the plus and minus they prob want 4 distinct answers
or maybe they want a decimal approximation
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yes i did and the example is written as your answer
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