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\[\int\limits_{}^{}\left(1/x +2/x^2+ 3/x^3\right)\]
convert it to negative exponents and integrate each term
\[1 \int\limits_{} x^{-1} +2\int\limits_{}x^{-2} +3\int\limits_{}x^-3\]
i have this for the answer \[\left| x \right| \ln 2/x +3/x^2 \]
\[\ln(x) +\frac{2x^{(-1+1)}}{-1+1} + \frac{3x^{(-3+1)}}{-3+1}\]
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^(-2+1)...typoed it lol
ln(x) -(2/x) -(3/2x^2)
....+C ; cant forget the +C at the end
ok thanks i missed so steps but i got it thank
i missed some to, but I think I wrangled them all in at the end :)
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