Question

how do you solve a vertical hyperbolas that looks like this : ( y^2-2y )-4(x^2 )= 36?

Answer 1

what do you mean by "solve"?

Answer 2

(y^2-2y )-4(x^2 )= 36

complete the squares :)

Answer 3

-4x^2 is already fine....nothing needed there

y^2 -2y + _____ ; (-2/2)^2 = 1

y^2 -2y +1; since you add 1 to this side; add it to the other side as well....

Answer 4

or is it just asking for the complete the square info?

Answer 5

thank you

Answer 6

its asking to complete the square info