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OpenStudy (anonymous):
ac method step by step plz 3x³-5x²-2x
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OpenStudy (anonymous):
still don't get help?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
x^3 you need made x^2 for easy facteor
OpenStudy (anonymous):
first GCF = x
OpenStudy (anonymous):
after put GCF out side you have
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OpenStudy (anonymous):
\[x(3x^{2}-5x-2)\]
OpenStudy (anonymous):
factor;
x(x-2)(3x+1)
OpenStudy (anonymous):
very hard hard to explain,you may watch web site, www.youtube.com more easy understand
OpenStudy (anonymous):
3x^3 you bring out side x now you have 3x^2
5x^2 you bring out side x now you have 5x
2x you bring out side x now you have 2
OpenStudy (anonymous):
ok can u do
8x²-16-28x
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OpenStudy (anonymous):
this is decimal you have to use quadratic equation form can't not factor
(-b ∓√(b^2-4*a*c))/2a
OpenStudy (anonymous):
did you do this before?
OpenStudy (anonymous):
a=8
b=-16
c=-28
OpenStudy (anonymous):
(-(-16) ∓√(-16)^2)-(4*8*(-16))/2(8)
OpenStudy (anonymous):
i have to explain it step by step to another student using the ac method
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OpenStudy (anonymous):
I only know this way
OpenStudy (anonymous):
you may repost to see some one know how to do using the ac method
OpenStudy (anonymous):
Ok. I have to go now bye
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