Question

ln5x+lnx=7

Answer 1

ln (5x^2) = 7

5x^2 = e^(7)

Answer 2

\[x^2 = (1/5)e^7\]

\[x= +- \frac{1}{\sqrt{5}} e ^{7/2}\]

Answer 3

but , x cannt be a negative number , otherwise we will take the log of a negative ( which is undefined) when we sub into the original equations

so

Answer 4

\[ x = \frac{1}{ \sqrt{5}} e ^{7/2}\]

is the only solution

Answer 5

okay thank you very much.