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solve the equation: x+2x^1/2-4=0
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let u=x^(1/2) u^2 +2u -4 =0
k
i dont know where to go from there
quadratic formula, or completing the sqaure
so u^2 + 2u = 4 u^2 +2u +1 = 4+1 (u+1)^2 = 5
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u+1 = +_sqrt(5)
u = -1 +- sqrt(5)
so sqrt(x) = -1 + sqrt(5) and sqrt(x) =-1-sqrt(5)
so the first equation gives x= ( sqrt(5) -1 ) and the second eqn gives no solution ( a sqrt cannot be negative )
ok i got it now
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