The perimeter of a rectangle is 38m. The length is 10m more than twice the width. Find the demensions.
What is the lenght?
?=m
Simplify your answer
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OpenStudy (anonymous):
6
OpenStudy (anonymous):
sorry, 16m
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
try setting up the equations: you know that the perimeter of a box is twice the length + twice the width
OpenStudy (anonymous):
so let's use w for width and l for length
we have that 2w+2l = 38
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OpenStudy (anonymous):
but you are told that the length is 10 more than twice the width...so can you write that in equation form? i'll get you started....
length = 2 times width plus 10 (<=== write that in equation form)
OpenStudy (anonymous):
what is the width I got -L+19
OpenStudy (anonymous):
so you have w = -L + 19?
OpenStudy (anonymous):
try plugging in your length...we know length is equal to 16
OpenStudy (anonymous):
what do you get?
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OpenStudy (anonymous):
so... w = -(16) + 19 = ?
OpenStudy (anonymous):
3
OpenStudy (anonymous):
correct
test your answer...does everything work out?
OpenStudy (anonymous):
remember our original idea....that 2*length + 2*width = 38, your perimeter