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Need help finding the vertex
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\[y=(x-4)^{2}+5\]
vertex of a parabola is \[x = -\frac{b}{2a}\]
does a=1 b=4 and c=5 or is there just no c so i substitute with 0?
the vertex is given to you in that form the x is shifted by 4 and y by 5 so the vertex would be (4, 5)
ohh ok. thanks!
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can u try helping me
with the ice cream one?
lol we tried helping you chickaaaaaa (<--^_^) but u wouldnt repond!! :P
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