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Calculate the value of the expression using properties of logs: a.) log[12]6 + log[12]2 = b.) log[8]2 + log[8]32 =
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a. = log [12] ( 6x2 ) = log [12](12) =1
log(a)x+log(a)y=log(a)xy
b. log [ 8] ( 2 x 32 ) = log [8] (64) = log [8](8^2) = 2
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