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Mathematics 14 Online
OpenStudy (anonymous):

How does one integrate sqrt(x+1) ?

OpenStudy (anonymous):

(3/2)[(x+1)^3/2]

OpenStudy (anonymous):

Why is it multiplied by (3/2) in the front rather than (2/3)?

OpenStudy (anonymous):

oh yes :)

OpenStudy (anonymous):

thanks

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