determine whether the DE is exact:

y^2dx - x^2dy=0

Question

determine whether the DE is exact:

y^2dx - x^2dy=0

amistre64 · Answer

[S] dy/(y^2) = [S] dx/(x^2)

amistre64 · Answer

DE is exact?  whats that mean? :)

anonymous · Answer

using the exact method

amistre64 · Answer

ahh..... and what is the exact method?  :)

anonymous · Answer

use the test for exactness: take partial derivative of M with respect to y and partial derivative of N with respect to x and see if they provide the same answer
.....its more complicated. the exact method is a part of solving differential equations

amistre64 · Answer

ive seen that in the textbooks before, but cant recall the details of it :)

anonymous · Answer

a DE is exact if
 partial derivative of coefficient of x with respect to y is equal to partial derivative of coeff of y with respect to x. It an equation is exact there is an easy method to solve it.

anonymous · Answer

correction; coefficients of dx and dy