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How do I find the answer to a cubed + 27t cubed by factoring
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a^3 +27t , is that the question?
There is a theorem on how to factor cubics. (a - b)(a + 2ab + b) I think?
27t^3; and davis is correct :)
Sorry thats backwards. \[(a+b)(a^2 - 2ab + b^2)\]
lol..... semantics :)
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a = a, b = 27t
Sorry first time using this site...not sure how to enter the problems
Sorry its still wrong, \[(a + b)(a^2 - ab + b^2)\]
enter them the best you can and clarify as needed really :)
(a^3 +- b^3) (a +- b)(a^2 -+ ab + b^2)
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Thank you..ok so which one am I to use? The question is a to the third power or cubed + 27t to the third power or cubed
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