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OpenStudy (anonymous):
Ok... I'm overwhelmed! (8^-6+7^-8)^0*5*2^-1+2*4^-1*2*3^-2+3*9^-1*(4^-1+3^-2)^0
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OpenStudy (anonymous):
any number to the power of 0 is one this simplifies a lot. after that just use BOMDAS rules to evaluate
OpenStudy (anonymous):
so I'm correct in saying the answer is [1z5x(1/2)]+[(1/9)]+[(1/3)]52/18 ?
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