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a = i +2j -3k and b = -2i -j +5k are two vectors, how to find the angle between the vectors and how to find a vector that is perpendicular to vector a
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Try using inner product: Angle = arccos[(a dot b)/(|a||b|)]
Dot <12,-3>.<-2,-1,5>
how do I get the vector perpendicular - second part of the question
Cross the 2 vectors, result is vector perpendicular
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