Question

SOMEONE PLEASE HELP!
A rectangular yard measuring 40 ft by 71ft is bordered (and surrounded) by a fence. Inside, a walk that is 3 ft wide goes all the way along the fence. Find the area of this walk. Be sure to include the correct unit in your answer.

Answer 1

is 40ft the length and 71ft the width of the yard?

Answer 2

i'm guessing. that is how it is written. so yes.

Answer 3

it is worded really weird

Answer 4

ok then, if 40ft is the length, u can multiply that times the width of the walk, so 3 ft, 40*3= 120...i think that would be the area 120 sq ft

Answer 5

it said that was incorrect

Answer 6

it will show me how to do it. and iwill tell u. then will u heelp me with the next 2 problems like this one?

Answer 7

sure ill try to help u

Answer 8

We start by drawing a rectangle representing the fence surrounding the yard.
Inside the fence, we draw a wide walk going along the fence.
inner rectangle's length is the yard length twice the walk width. so 71-3-3=65 ft and the width is 40-3-3=34 ft

Answer 9

since the walk is the region between the 2 rectangles..it's area is the area of the larger rectangle minus the area of the smaller rectangle.
so a=40x71-34x65
=2840-2210
=630 ft ^2

Answer 10

follow? bc it's kinda confusing to me.

Answer 11

yes, i think i follow

Answer 12

ok, i got it :)

Answer 13

it sounds more like a rectangular box?

Answer 14

i know. this thing is so stupid..but i think i have the hang of it now.

Answer 15

It kinda makes sense, otherwise you might include the corners twice.

Answer 16

Did you work the next one?